C/P 08 · Sound waves and hearing
Sound, Pipes and the Ear
Use standing waves, the Doppler effect and decibels, then connect them to the cochlea.
Passage
Sound is a longitudinal wave in which regions of high and low pressure travel through a medium. The speed of sound in air is about 340 m/s, and the speed, frequency f and wavelength λ of any wave are related by v = fλ. When a source of sound and an observer move relative to each other, the observed frequency differs from the source frequency. This is the Doppler effect. For a source moving toward a stationary observer at speed vₛ, the observed frequency is f′ = f · v/(v − vₛ), and for a source moving away from the observer, f′ = f · v/(v + vₛ). The Doppler effect changes the frequency that reaches the observer. It does not change the speed of the wave in the air.
The loudness of a sound is described by the sound intensity level β, measured in decibels (dB): β = 10 log₁₀(I/I₀), where I is the intensity and I₀ = 10⁻¹² W/m² is close to the quietest sound a person can hear. A tenfold increase in intensity raises the level by 10 dB. For a small source in open air, the intensity falls in proportion to the inverse square of the distance from the source.
Part 1. A student studies resonance in two tubes of the same length, 0.85 m. Tube A is open at both ends, and Tube B is closed at one end and open at the other. She holds a tuning fork of variable frequency at the open end and records the frequencies at which the sound inside becomes much louder. Table 1 shows the lowest two resonant frequencies for each tube.
Table 1. Resonant frequencies of two tubes, each 0.85 m long.
| Tube | Ends | Lowest resonant frequency (Hz) | Second-lowest resonant frequency (Hz) |
|---|---|---|---|
| A | Open at both ends | 200 | 400 |
| B | Closed at one end | 100 | 300 |
Part 2. A student stands beside a straight road and records the frequency of an ambulance siren that emits a steady tone of 400 Hz as measured by the driver. The ambulance drives at constant speed past the student. Table 2 shows the frequency the student hears as the ambulance approaches and as it moves away.
Table 2. Frequency of a siren heard by a stationary student.
| Situation | Frequency heard (Hz) |
|---|---|
| Ambulance approaching | 425 |
| Ambulance moving away | 378 |
Part 3. The student then measures the sound intensity level from a small loudspeaker in an open field at several distances. Table 3 shows the results.
Table 3. Sound level at different distances from a loudspeaker.
| Distance from the speaker (m) | Sound intensity level (dB) |
|---|---|
| 1 | 80 |
| 2 | 74 |
| 10 | 60 |
The ear detects sound through a series of structures. The eardrum vibrates in response to pressure variations, and three small bones transmit the vibrations to the oval window, an opening in the fluid-filled cochlea. Inside the cochlea, the basilar membrane is narrow and stiff near the oval window (the base) and wide and flexible at the far end (the apex). Different frequencies cause the largest vibrations at different positions along the membrane, and hair cells at those positions send signals to the brain.
Questions
Question 1 of 6
Which of the following frequencies would Tube B also resonate at?
Tube B, closed at one end, supports only odd multiples of its fundamental (100, 300, 500 Hz). 200 Hz is an even multiple.
This is also an even multiple of 100 Hz, and a closed-end tube does not resonate at even harmonics.
This is an even multiple (6 × 100 Hz). A tube closed at one end supports only odd harmonics.
Why the answer is what it is
Tube B has a node at the closed end and an antinode at the open end, so only odd harmonics fit: 100, 300, 500 Hz, and so on. The open tube A supports all harmonics (200, 400, 600 Hz).
Review: Sound & Acoustics · Waves & Harmonics · Hearing & Sound · Equations: Waves, Optics & Modern Physics
Question 2 of 6
What is the wavelength of the lowest-frequency standing wave in Tube B?
This is the length of the tube. For a tube closed at one end, the length is only a quarter of the wavelength.
This is the wavelength of the lowest resonance of the open tube (2L). The closed tube’s fundamental is longer.
This is eight times the tube’s length. The fundamental of a closed tube has λ = 4L, not 8L.
Why the answer is what it is
In a tube closed at one end, the fundamental has a node at the closed end and an antinode at the open end, so L = λ/4 and λ = 4 × 0.85 = 3.4 m. This agrees with v = fλ: 100 Hz × 3.4 m = 340 m/s.
Review: Sound & Acoustics · Waves & Harmonics · Hearing & Sound · Equations: Waves, Optics & Modern Physics
Question 3 of 6
What is the speed of the ambulance in Part 2?
A speed of 10 m/s would give an approaching frequency of 400 × 340/330 ≈ 412 Hz, not 425 Hz.
This is the difference between 425 Hz and 400 Hz, in hertz. It is not a speed.
A speed of 40 m/s would raise the frequency to about 453 Hz.
Why the answer is what it is
Using f′ = f · v/(v − vₛ), 425/400 = 340/(340 − vₛ). The ratio 425/400 is 17/16, so 340 − vₛ = 320 and vₛ = 20 m/s.
Review: Sound & Acoustics · Waves & Harmonics · Hearing & Sound · Equations: Waves, Optics & Modern Physics
Question 4 of 6
Why is the frequency heard higher while the ambulance approaches?
The speed of sound depends on the medium and is not changed by the motion of the source.
The driver measures the same 400 Hz at all times. The change is in what the observer receives.
The change is due to the physics of the waves, not to the student’s hearing.
Why the answer is what it is
Each wave crest is emitted from a point closer to the observer than the previous one, so the crests are bunched up (shorter λ). With the speed of sound unchanged, v = fλ means that a shorter wavelength reaches the observer at a higher frequency.
Review: Sound & Acoustics · Waves & Harmonics · Hearing & Sound · Equations: Waves, Optics & Modern Physics
Question 5 of 6
How does the sound intensity (in W/m²) at 10 m compare with the intensity at 1 m?
Intensity levels in dB are logarithmic, and a fall of 20 dB is not a factor of 20.
A tenfold decrease in intensity would lower the level by 10 dB. The table shows a fall of 20 dB.
A factor of one thousandth would lower the level by 30 dB.
Why the answer is what it is
The level falls from 80 to 60 dB, which is 20 dB. Every 10 dB is a factor of 10 in intensity, so the intensity is lower by 10 × 10 = 100. This also follows from the inverse-square law: 10 times the distance gives 1/100 of the intensity.
Review: Sound & Acoustics · Waves & Harmonics · Hearing & Sound · Equations: Waves, Optics & Modern Physics
Question 6 of 6
Compared with a 400 Hz tone, a 4000 Hz tone would cause the largest vibration of the basilar membrane:
Different positions along the membrane respond to different frequencies, which is how pitch is encoded.
The apex responds best to low frequencies. A high-frequency tone is detected near the stiff base.
High frequencies travel through the ossicles to the cochlea in the same way as lower ones.
Why the answer is what it is
The basilar membrane is stiff and narrow at the base and responds best to high frequencies, and it is flexible and wide at the apex and responds best to low frequencies.
Review: Sound & Acoustics · Waves & Harmonics · Hearing & Sound · Equations: Waves, Optics & Modern Physics
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